4c^2-20c+25=0

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Solution for 4c^2-20c+25=0 equation:


Simplifying
4c2 + -20c + 25 = 0

Reorder the terms:
25 + -20c + 4c2 = 0

Solving
25 + -20c + 4c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + -2c)(5 + -2c) = 0

Subproblem 1

Set the factor '(5 + -2c)' equal to zero and attempt to solve: Simplifying 5 + -2c = 0 Solving 5 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2c = 0 + -5 -2c = 0 + -5 Combine like terms: 0 + -5 = -5 -2c = -5 Divide each side by '-2'. c = 2.5 Simplifying c = 2.5

Subproblem 2

Set the factor '(5 + -2c)' equal to zero and attempt to solve: Simplifying 5 + -2c = 0 Solving 5 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2c = 0 + -5 -2c = 0 + -5 Combine like terms: 0 + -5 = -5 -2c = -5 Divide each side by '-2'. c = 2.5 Simplifying c = 2.5

Solution

c = {2.5, 2.5}

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